7.1

Ian Henny Period - 3rd
 * 7.1 - Solve Linear Systems by Graphing**
 * Types of Linear Systems**
 * Solving a Linear System Using the Graph-and-Check Method**
 * Solve Multi-Step Problem**
 * Intersect Point**


 * Problem #1**
 * __Check Intersect Point__**


 * x + 2y = 7 Equation #1**
 * 3x - 2y = 5 Equation #2**



__**Solution for Problem #1**__

__**Equation #1**__
 * x + 2y + 7**
 * 3 + 2 (2) = 7**
 * 7 = 7**

__**Equation #2**__
 * 3x-2y = 5**
 * 3(3)-2(2) = 5**
 * 5 = 5**

Lines intersect at (3.2) Check Answer to see if correct

__**Problem**__ **#2**
 * Use the Graph-and-check method**


 * x + y = -7 Equation #1**
 * x + 4y = -8 Equation #2**




 * __Solution for Problem #2__**


 * __Equation #1__**
 * -x + y = -7**
 * -(4) + (-3) = -7**
 * -7 = -7**

__**Equation #2**__
 * X + 4y = -8**
 * 4 + 4 (-3) = -8**
 * -8 = -8**

Lines intersect at (4,-2) Check Answer to see if correct

5.4.2011 Period 7 Algebra 1 Van Aulen
 * Danielle Schott**

(7.1) Solve Linear Systems by Graphing
o to a system of linear equations in two variables is an ordered pair. If lines intersect at a single point, then the coordinates of the point are the solution of the linear system.
 * Main Ideas:** A solution

Problem #1:
 * Is the ordered pair (15,5) a solution of the system of equations?**
 * y=1/3x**
 * 2x-y=25**

Solution for problem #1:
 * 1) Substitute the given ordered pair in the first equation.**
 * 5=(1/3)15**
 * 2) Simplify the right side by diving by the first fraction** second equation.


 * 2(15)-5=25**


 * 5=5**
 * The given ordered pair is a solution of the first equation.**
 * 3)Substitute the value 15 for x and 5 for y in**


 * 4) Simplify let side.**
 * 30-5=25**
 * 25=25**
 * The given ordered pair is a solution of the second equation-therefore, the given ordered pair is a solution of the system.**

Problem #2:
 * Is the ordered pair (1,3) a solution for the given system of equations?**
 * 3x+5y=18**
 * x-3y=-8**